dsbezji539113152 2015-03-25 04:53
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如何从html表单或php获取文件根值

I want to save directory root value of file to database.

ex: I have file with directory c:\xampp\htdocs\myproject\app\views\index.php , but i just want get myproject\app\views\index.php. I want to get value from the input type file, is it possible ?

This is how proccess I want to build, but the value not like I want.

not like what i want

i want when user click choose file in <input type='file' />, i want default directory open in "myproject" . it's not about uploading file, i just want make validation from directory root value. in some case i have 2 file with same name "index.php", but one of file located in myproject\view\dir1\index.php and another one in myproject\view\dir2\index.php. so that sets it apart is the root directory.

thanks for help me.

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  • drcx71276 2015-03-25 05:34
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    You can use the follwing:

    \Yii::$app->basePath will give like D:\xampp\htdocs\advanced\backend

    \Yii::$app->request->BaseUrl will give like localhost\advanced\backend\web\

    You may store the image using \Yii::$app->basePath and show it using \Yii::$app->request->BaseUrl

    Hope it helps

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