你可以在嵌入在php中的html中嵌入php指令吗？

Question

I tried something like this:

// $count is an incrementing number
echo '<td><input type = "radio" name = "selected" 
      value = "<?php echo htmlspecialchars($count); ?>"></td>';

I also tried:

echo '<td><input type = "radio" name = "selected" value = "<?php echo 
"$count"; ?>"></td>';

and neither worked. I realize it may seem strange to attempt to write html with php in this way, but I don't know how else to display html based off certain conditions.

Adding entire function that snippet is in:

function makeRow($row_name,$row_ticket) {
//create html table row from mysql table row passed as ticket object param
$count = 0;
foreach ($row_array as $key => $value) {
   # code...
   $count++;
   if(strcmp($key, "select")==0){
     echo '<td><input type = "radio" name = "selected" 
     value ="' . <?php echo htmlspecialchars($count); ?> . '"></td>';
   }
   else if(strcmp($key, "body")==0){/*do not make cell for body*/}

   else { echo "<td>$value</td>";}
 }

}

Answer 1

It cannot work because you can't concatenate a string like that it throws php parse error. I have not enough reputation for commenting so I add my own answer:

// $count is an incrementing number
echo '<td><input type = "radio" name = "selected" 
value ="' . htmlspecialchars($count) . '"></td>';

You can't add new php open/close tag inside another one.

Update:

Actually, you don't need htmlspecialchars() function for just outputing script - generated integer variable, so you can skip that too.