douyi1982 2015-02-20 20:06
浏览 47
已采纳

PHP mysql_connect与false变量

.Hello, I'm reading through some code and am not sure if I'm understanding this fully. This is supposed to connect to a mysql database:

if (!$dblink[$dblinkname] = mysql_connect($dbhost, $dbuser, $dbpass, true)) {
        //Throw error message
    }

Is this saying that if the dblink's name is empty then attempt to mysql_connect()? If I'm wrong on this any pointers would be appreciated! Thanks!

  • 写回答

2条回答 默认 最新

  • dongshi1424 2015-02-20 20:14
    关注

    The statement is first assigning whatever value is returned by mysql_connect function to $dblink[$dblinkname] variable.

    Now, if the connection is made, it will return the link resource and the condition will not be false hence it will not throw error.

    But if connection is not made, the returned value would be false, which will make the condition(!$dblink[$dblinkname]) true, hence it will execute error handling code.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥30 求一段fortran代码用IVF编译运行的结果
  • ¥15 深度学习根据CNN网络模型,搭建BP模型并训练MNIST数据集
  • ¥15 lammps拉伸应力应变曲线分析
  • ¥15 C++ 头文件/宏冲突问题解决
  • ¥15 用comsol模拟大气湍流通过底部加热(温度不同)的腔体
  • ¥50 安卓adb backup备份子用户应用数据失败
  • ¥20 有人能用聚类分析帮我分析一下文本内容嘛
  • ¥15 请问Lammps做复合材料拉伸模拟,应力应变曲线问题
  • ¥30 python代码,帮调试,帮帮忙吧
  • ¥15 #MATLAB仿真#车辆换道路径规划