dsg7513 2014-11-10 22:42
浏览 64
已采纳

JSON.parse意外的令牌多维数组

Hello I have simple question. I have some data fetched from database and json encoded and sent to html file over AJAX from PHP script. I want to JSON parse that data. Data looks like this:

enter image description here

And in PHP file like this:

$profesors = array
                (
                'id' => ($id),
                'name' => ($profesor)
                );

When I try to JSON parse it with JSON.parse() command I get "unexpected token {". Does anyone have some suggestion what to do? Also if it would be easier for achieving my goal I can use some other data type than array I am using, if someone knows better way...

EDIT

my PHP code that generates 2d array

<?php
$var=$_POST["oblast"];
$connection = mysql_connect('localhost','root','pass');
if (!$connection) {die("not successfull" . mysql_error());}

$result = mysql_query('set character set utf8', $connection); 
$result = mysql_query('set names utf8', $connection);
$db_select = mysql_select_db("fakultet",$connection);
$brojac=0;
$profesor="";
//$data = array(array());
$queryData = mysql_query("SELECT * FROM predmet WHERE idpred = '$var'");
while($result1 = mysql_fetch_array($queryData))
{
$prof=$result1['idprof'];
    $queryData1 = mysql_query("SELECT * FROM profesori WHERE idprof = '$prof'");
        while($result2 = mysql_fetch_array($queryData1))
        {

            $id=$result2['idprof'];
            $profesor=$result2['ime']." ".$result2['prezime'];
            $profesors = array
                (
                'id' => ($id),
                'name' => ($profesor)
                );

            echo json_encode($profesors);

        }
    //echo($result1['idprof']);
    //$data[]=$result['idprof'];

}

//echo "$data";
?>
  • 写回答

2条回答 默认 最新

  • dtzhfb4869 2014-11-11 00:01
    关注

    You are doing echo json_encode($profesors); inside your while loop. Don't do that. You should only ever call json_encode once.

    Try something like this:

    $profesors = array();
    
    while($result2 = mysql_fetch_array($queryData1))
    {
        $id=$result2['idprof'];
        $profesor=$result2['ime']." ".$result2['prezime'];
        $profesors[] = array(
            'id' => $id,
            'name' => $profesor
        );
    }
    
    echo json_encode($profesors);
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥15 fpga自动售货机数码管(相关搜索:数字时钟)
  • ¥20 Python安装cvxpy库出问题
  • ¥15 用前端向数据库插入数据,通过debug发现数据能走到后端,但是放行之后就会提示错误
  • ¥15 python天天向上类似问题,但没有清零
  • ¥30 3天&7天&&15天&销量如何统计同一行
  • ¥30 帮我写一段可以读取LD2450数据并计算距离的Arduino代码
  • ¥15 C#调用python代码(python带有库)
  • ¥15 活动选择题。最多可以参加几个项目?
  • ¥15 飞机曲面部件如机翼,壁板等具体的孔位模型
  • ¥15 vs2019中数据导出问题