传递.php文件作为参数

Question

Perhaps I'm going about this the wrong way, but I have a Configuration file that I'm trying to pass through a parameter, the reason I'm doing this is because I'm experimenting with what I call a ("Core"/"Client") structure, probably not the correct name, but basically whatever I edit on the "Core" is updated to all of the "Client" subdomains, which will respectively call code such as

include '/path/to/core/index.php';
generateIndex($Param, $Param);

So, Basically, here's what I have, on the "Clients" side I have a Configuration file, called "Configuration.php" this holds all of the static variables pertaining to the Clients database. Example below:

<?php
    $SQL_HOST = "";
    $SQL_DATBASE = "";
    $SQL_ACCOUNT_TABLE = "";
    $SQL_DATA_TABLE = "";
    $SQL_REWARDS_TABLE = ""; 
    $SQL_USERNAME = "";
    $SQL_PASSWORD = "";
?>

So, Basically, I'm trying to do this,

generateIndex($SQLConnection, $Configuration);

However, It's not allowing me to do so and presenting me with this error.

Notice: Undefined variable: Configuration in /opt/lampp/htdocs/client/index.php on line 16

Respectively, Line 16 is the line above containing "generateIndex"

Now, on the "Core" side what I'm trying to do is the following to get data.

function generateIndex($SQLConnection, $SQLConfig) {
    ...
        $SQLConfig->TBL_NAME
    ...
}

Which I don't know if it throws an error yet, because I can't pass $Configuation to the function.

Answer 1

Your can user return context for get variable from file.

As example:

File db_config.php:

<?php 
return array(
  'NAME' => 'foo_bar',
  'USER' => 'qwerty',
  'PASS' => '12345',
  // Any parameters
);

You another file with include configuration:

<?php
// Code here...
$dbConfig = include 'db_config';
// Code here

If file have a return statement, then your can get this values with = operator and include file.