duanjiao6731
duanjiao6731
2014-05-08 14:44

以列表形式读出并显示txt文件的内容

已采纳

I have a script that lists all txt files in a folder. What i want to do is to display the file contents instead of the filename. but i dont succeed... i tried readfile and filegetcontents but i get only .txt name

<?php
if ($handle = opendir('../plugins/guestbook/news/')) {
    while (false !== ($file = readdir($handle))) {
        if ($file != "." && $file != "..") {
            echo "<center><label class='tablog3a'>$file <div style='float: right;margin-top:10px;'><a href='gbremove.php?file=".$file."'><img src='images/deletegb.png' title='Verwijder afbeelding' class='clickreverse'></a></div></label></center>";
        }
    }
    closedir($handle);
}
?>

i tried also

<?php
if ($handle = opendir('../plugins/guestbook/news/')) {
    while (false !== ($file = readdir($handle))) {
        if ($file != "." && $file != "..") {
$txtfile = file_get_contents('$file');
            echo "<center><label class='tablog3a'>$txtfile<div style='float: right;margin-top:10px;'><a href='gbremove.php?file=".$file."'><img src='images/deletegb.png' title='Verwijder afbeelding' class='clickreverse'></a></div></label></center>";
        }
    }
    closedir($handle);
}
?>
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1条回答

  • duanjia3187 duanjia3187 7年前

    This works for me:

    <?php 
    $dir = "your_directory/"; // Your directory
    
    if ($handle = opendir($dir)) {
      while (false != ($file = readdir($handle))) {
          // Check for .txt files
          if ($file != "." && $file != ".." && substr($file, -3) == "txt") {
            // Open file to read
            $fp = fopen($dir.$file, 'r');
    
            // Print contents
            echo fread($fp, filesize($dir.$file)).'<br />';
          }
      }
      closedir($handle);
    }?>
    

    cheers

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