dongzong8110 2014-01-06 20:04
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使用PHP array_diff并没有正确比较

I'm trying to use array_diff to compare a list of values pulled from a table with one I set manually and it's not working, not even close. It's like it doesn't recognise the array I build from the query, and just outputs array1 unchanged. Any idea where i'm going wrong? I've tried putting them the other way around, i've tried different ways of building array2 in the query, and nothing seems to help.

$open_positions_query = "SELECT position FROM ship_positions WHERE ship_id = '$ship_id'";
$open_positions_result = mysqli_query($mysqli, $open_positions_query);
while ($open_positions_array = mysqli_fetch_row($open_positions_result))
{
   $array2[] = array($open_positions_array);
}

$array1 = array("CO", "XO", "OPS", "NAV", "CTO", "TAC", "CMO", "MED", "CSO", "SCI", "CEO", "ENG", "CIV");   

$arrayresult = array_diff($array1, $array2);

I've got it outputting elsewhere, and right now it just outputs array1 unchanged. If I put this in though, it outputs the correct difference.

$array2 = array("CO", "XO", "OPS", "NAV", "CTO", "TAC", "CMO", "SCI", "CEO");
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  • dsdzvprlp51692469 2014-01-06 20:09
    关注

    Try this :

    while ($open_positions_array = mysqli_fetch_row($open_positions_result))
    {
       $array2[] = $open_positions_array['position'];
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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