dongnanbi4942 2013-12-18 09:55
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如何将带有链接的字符串拆分为PHP中的数组或对象,并丢弃所有不属于该URL的内容?

I have a list of links in my db column and when I grab it from the db it looks like this (obviously, it's much longer in reality):

http://example.com/asdfasdf/erwr
http://asdfasdfas.com/asdfasd/fasdf/asdfas.mp3
http://asdfa.com/adsf/asdf/asdf/asdf.html

or it can looks like this:

http://example.com/asdfasdf/erwrhttp://asdfasdfas.com/asdfasd/fasdf/asdfas.mp3

or it can looks like this:

http://example.com/asdfasdf/erwr, http://asdfasdfas.com/asdfasd/fasdf/asdfas.mp3

so I think that the indication of a new link is the beginning http:// which will probably be not in the url itself except in the begining of that url.

So, the problem is how to explode this list in PHP and create an array or object with links and throw away all the other html like <br> or commas and spaces etc.

Any idea how to do that in PHP?

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  • dongquanjie9328 2013-12-18 10:01
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    You can explode string into array and can get your required string. For example

    $url = http://example.com/asdfasdf/erwr
    $string = explode('//',$url);
    echo $string[1];
    
    //output example.com/asdfasdf/erwr
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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