语法错误php代码我无法回显变量

Question

I'm having some problems with this code in PHP echo, I want if variable if empty then show an image name "no-registrado.png"

<?php echo $registro ?: "no-registrado.png"; ?>

the error: Parse error: syntax error, unexpected ':' in /Republica-Dominicana/negocios.php on line 199

<img src="../imagenes/admin/<?php echo $registro ?; "no-registrado.png" ?>" Alt="Registrado" title="Registrado" width="20" height="20"/>

Answer 1

Short form of the ternary operator ($registro ?: "no-registrado.png") is available since PHP 5.3. Probably your current version of PHP is less than 5.3.

You can use full form if you have PHP < 5.3:

$registro ? $registro : "no-registrado.png"

Also, in your code, you have semicolon in the place where you need use colon.

<?php echo $registro ?; "no-registrado.png" ?>