PHP中类的静态运算符的命名空间？

Question

The documentation says

The namespace keyword can be used to explicitly request an element from the current namespace or a sub-namespace. It is the namespace equivalent of the self operator for classes.

I need the equivalent of static instead, ie. if a class extends my class, the namespace of that.

This

 return preg_replace('/.[^\\\\]+$/', '', get_class($object));

does it but it makes me sad.

Answer 1

Reflection provides an effective way of doing this via ReflectionObject->getNamespace(), check the following code:

namespace Foo {
    class Bar {
        public function getNamespace() {
            return (new \ReflectionObject($this))->getNamespaceName();
        }
    }
}

namespace Baz {
    use Foo\Bar as BaseClass;

    class Bar extends BaseClass {}
}

namespace {
    $bar1 = new Foo\Bar();
    echo "ns1 is: ", $bar1->getNamespace(), '<br>';

    $bar2 = new Baz\Bar();
    echo "ns2 is: ", $bar2->getNamespace();
}