doulei1965 2011-11-11 21:30
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在PHP中基于父方法定义属性

class UserInfo extends Database{

    private $privileges=
        $this
            ->connect()
            ->select("users", "DISTINCT privileges", "username= 'someuser'")
            ->getResult('privileges');

}

It doesn't seem like it is possible for me to be able to define this property $privileges based on a method based on the parent class Database.

It is worth pointing out the same function works splendidly when I use the same function in a different script and define the properties dynamically. Each class is instantiated by an object, it works (obviously with the proper setters and getters.)

$db = new Database;
$user = new UserInfo;
$user-> privileges= 
    $db
        ->connect()
        ->select("users", "DISTINCT privileges", "username= '".$user->name."'")
        -> getResult('privileges');
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2条回答 默认 最新

  • dony39517 2011-11-11 21:34
    关注

    You can't put an expression when defining a property's value inside a class. Use the constructor for that:

    <?php
    class UserInfo extends Database
    {
        // ...
    
        public function __construct()
        {
            // initialize the 'privileges' property
        }
    }
    ?>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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