PHP只显示$ value，直到$ value更改为止

Question

Hi I have the following table that is generated from my database, it looks like this

The problem is I dont want the dates to repeat. If there is more than one fixture for a specific date, I only want the date displayed once and then the fixtures under the date.

Example In this case, on the image, Today,2015-04-23 must be displayed only once and then the 2 team names under it.

Im using the following code

$echoed = false;

while($row = > $played){

$gameDate = $row['event_date'];
$team1 = $row['team1'];
$team2 = $row['team2'];
$venue = $row['venue'];
$eventId = $row['event_id'];



    if($gameDate == $date && !$echoed){

    echo'<tr>'; 
    echo $echoed ='<td>Today,'.$gameDate.'echo</td>';
    echo'</tr>';
    echo'<tr>';
        echo'<td>'.$team1.'</td>';
        echo'<td>'.$team2.'</td>';
        echo'<td>'.$venue.'</td>';
        :
        :

However code above is not giving desired result and returns result same as per image above

Answer 1

You can check, if the date is the same as the one before:

<?php
$lastDate = '';

while($row = > $played){

$gameDate = $row['event_date'];
$team1 = $row['team1'];
$team2 = $row['team2'];
$venue = $row['venue'];
$eventId = $row['event_id'];
if($gameDate !== $lastDate) {
echo'<tr>';
  $lastDate = $gamedate;
  echo $echoed ='<td>Today,'.$gameDate.'echo</td>';
echo'</tr>';
}
echo'<tr>';
echo'<td>'.$team1.'</td>';
echo'<td>'.$team2.'</td>';
echo'<td>'.$venue.'</td>';

Note: i removed your echoed code and your if-statement, because $date is undefined :)