Here is my full link.
<a href="http://localhost/mysite/client-portal/">Client Portal</a>
I want above link to look like following.
<a href="#popup">Client Portal</a>
I really don't know how to work with preg_replace to get this done.
preg_replace('\/localhost\/mysite\/client-portal\/', '#popup', $output)
分享 If is only this link you can achieve your goal with
str_replace():
<?php
$link = '<a href="http://localhost/mysite/client-portal/">Client Portal</a>';
$href = 'http://localhost/mysite/client-portal/';
$new_href = '#popup';
$new_link = str_replace($href, $new_href, $link);
echo $new_link;
?>
Output:
<a href="#popup">Client Portal</a>
If you want you can use DOM:
<?php
$link = '<a href="http://localhost/mysite/client-portal/">Client Portal</a>';
$new_href = '#popup';
$doc = new DOMDocument;
$doc->loadHTML($link);
foreach ($doc->getElementsByTagName('a') as $link) {
$link->setAttribute('href', $new_href);
}
echo $doc->saveHTML();
?>
Output:
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd">
<html><body><a href="#popup">Client Portal</a></body></html>
Or you can use
preg_replace()like this:
<?php
$link = '<a href="http://localhost/mysite/client-portal/">Client Portal</a>';
$new_href = '#popup';
$regex = "((https?|ftp)\:\/\/)?"; // SCHEME
$regex .= "(localhost)"; // Host or IP
$regex .= "(\/([a-z0-9+\$_-]\.?)+)*\/?"; // Path
$pattern = "/$regex/";
$newContent = preg_replace($pattern, $new_href, $link);
echo $newContent;
?>
Output:
<a href="#popup">Client Portal</a>
