dongya1228 2014-03-15 00:24
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在Codeigniter视图中使用变量作为数组名称

I passed $data array to view. $data array is like:

$data = array('t0' => array('point' => 0), 't1' => array('point' => 2) .... );

What I am trying to do is using this array in my view as follows:

<?php echo $t0['point']; ?> //It works!

But I am doing this in a for loop by definition of structure. Therefore I need to pass numeric value(near 't' letter) as a variable. How can I achieve this?

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  • douwen1313 2014-03-15 00:48
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    you can do like this:

    $count = count($data);   //if you know the count of $data
     for($i = 0; $i < $count; $i++) {
            $var = 't'.$i;
            echo ${$var}['point'];
        }
    
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