douxiapi4381 2013-10-29 21:04
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PHP按日期和年份分开数据

I have data like this

Title - August 2013
Title2 - August 2013
Title3 - October 2013

What I am trying to do is write up to separate these by date and return a link per a month and year, my expected results are:

August 2013
October 2013

I started writing this code:

<?php 

$data = array("Title - August 2013", "Title2 - August 2013", "Title3 - October 2013");

foreach($data as $index){

    $date = explode(" - ", $index);

    echo $date[1];

}

?>

I just don't know how I would go about the rest to only display a date once. I suppose I could create an array in the foreach and check if the date is inside the array.

Any ideas?

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1条回答 默认 最新

  • duanbo6482 2013-10-29 21:13
    关注

    Well, yea... Put dates to array and then remove duplications:

    $data = array('Title - August 2013', 'Title2 - August 2013', 'Title3 - October 2013');
    
    $dates = array();
    foreach($data as $index) {
        $date = explode(' - ', $index);
        $dates[] = $date[1];
    }
    
    $dates = array_unique($dates);
    
    var_dump($dates);
    

    Result will be:

    array (size=2)
      0 => string 'August 2013' (length=11)
      2 => string 'October 2013' (length=12)
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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