dongshen7561 2013-08-27 21:24
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sed相当于PCRE的`。?`

I'm trying to find all instances of aaa and replace it with bbb but preserving the first character preceding the aaa. Here's how I'd do it in PHP with PCRE:

preg_replace('#(.?)aaa#', '\1bbb', 'aaasdfg');

How would I do something like that with sed? Here's my attempt (didn't work):

sed -i.bak -r 's/(.\?)aaa/\1bbb/g' filename.ext

It's a bit of a contrived example. What I'm trying to do is a little more complicated but, long story short, I'm trying to get .? working.

Any ideas?

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  • dsfo22654 2013-08-27 21:36
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    Just now I mis-read your question, I thought you want to do .*? with sed. ..

    Ok, now I understand what you mean. In another question from you, I mentioned, for BRE, you have to escape those chars to give them special meaning. But for ERE, you have to escape chars which have special meaning to get literal string.

    You used -r, to let sed use ERE, but you escaped ?, it means, you want to match literal string ?.

    try this:

    sed -i.bak -r 's/(.?)aaa/\1bbb/g' filename.ext
    

    or this:

    sed -i.bak 's/\(.\?\)aaa/\1bbb/g' filename.ext
    

    test:

    default with BRE

    kent$  echo "aaasdf
    xaaasdf"|sed 's/\(.\?\)aaa/\1bbb/'
    bbbsdf
    xbbbsd
    

    with -r, ERE:

    kent$  echo "aaasdf
    xaaasdf"|sed -r 's/(.?)aaa/\1bbb/' 
    bbbsdf
    xbbbsdf
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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