把所有东西变成“......”之后; 这是句子中的第100个位置

Question

Here I have a string: "status; status;" and so on... I need to cut the string from the status where string is longer than 100 chars

for example: "status; status; status; (here is longer than 100 chars) ..."

previously I did it with the array:

 if($length_of_string > 100)
 { 
     $number_of_elements = count($statuses_array);
     echo $statuses_array[$number_of_elements-1];
     echo ' ... ';
     } else {
     echo $string_of_statuses;
}

but it is not good

thank you in advance!

Answer 1

How about:

$l = strlen($status_string);
if ($l > 100) {
   //Split string into array of statuses, to not break last status
   $ls = explode(";",$status_string);
   $new_status = "";
   $i = 0;
   //Check if there is room for the next status in $new_status without passing 100 chars
   while (strlen($new_status) < 100) {
      $new_status .= $ls[$i].";";
      $i++;
   }
   $new_status = substr($new_status,0,-1)."...";
}

Edit: simplified code, as the last status apparently can surpass 100 chars, which actually makes it easier