我是JAVA的初学者，在启动示例代码时候出现了问题
项目目录结构是这样的
这是link.jsp的代码
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>Insert title here</title>
</head>
<body>
<a href="LinkRequestServlet?pageNo=2&queryString=QST">下一页</a>
</body>
</html>
这是LinkRequestServlet的代码
package com.qst.chapter02.servlet;
import java.io.IOException;
import java.io.PrintWriter;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class LinkRequestServlet extends HttpServlet {
public LinkRequestServlet() {
super();
}
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
//设置请求的字符编码为UTF-8
request.setCharacterEncoding("UTF-8");
//设置响应文本类型为HTML,UTF-8
response.setContentType("text/html;charset=UTF-8");
//获取输出流
PrintWriter out=response.getWriter();
//获取请求数据
String pageNo = request.getParameter("pageNo");
String queryString = request.getParameter("queryString");
int pageNum=0;
if(pageNo!=null)
pageNum=Integer.parseInt(pageNo);
//响应输出数据
out.println("<p>请求的页数"+pageNum+"</p>");
out.println("<p>请求的查询字符是:"+queryString+"</p>");
out.flush();
out.close();
}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
}
}
点击下一页就会出现这样的404结果，不太明白问题是出在哪里
