dq_1984 2011-08-18 21:04
浏览 34

查询未显示结果

I am doing this query. It doesn't show me the result which in $products.

code:

$sql = "SELECT s*
     FROM Client_agent_approvals caa
     INNER JOIN Subscriptions s ON s.client_id = caa.client_id
     WHERE caa.agent_id = '$id'
     AND s.agent_id <> '$id'";
$result = mysql_query($sql);

$query = mysql_query($sql) or die("Error: " . mysql_error());

if ($result == "") {
    echo "";
}
echo "";


$rows = mysql_num_rows($result);

if ($rows == 0) {
    print("");
} elseif ($rows > 0) {
    while ($row = mysql_fetch_array($query)) {

        $product = $row['product'];

        print("Products they have are: $product");
    }
}
  • 写回答

2条回答 默认 最新

  • doulieyu0881 2011-08-18 21:21
    关注

    You have s*. I think you mean s.*. You should also use do... while for query iteration:

     $row = mysql_fetch_array($query);
    
     if(!$row) 
     {
         print('no rows');// a more useful message
     }
     else
     {
        do {
    
            $product = $row['product'];
    
             print("Products they have are: $product");
         }
         while($row = mysql_fetch_array($query));
    
     }
    

    mysql_num_rows actually counts all of the values returned, this does not. You can almost say that it is doing twice the work for the same result.

    Of course, all of this assumes that there were one or more rows returned to begin with. Can you confirm that you should be getting something by running this in MySQL directly?

    评论

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