php if-statement不回显div类中的字符串？

Question

Right now, the value of the variable $thumbs_number is +2.

When I place <?php if ( $thumbs_number == 2 ) { echo "high-rated"; } ?>"> right before the closing </div> I do get an output: high-rated.

but when I place it inside the div's class: <div class="topic-content <?php if ( $thumbs_number == 2 ) { echo "high-rated"; } ?>">.

nothing is output.

Any suggestions to fix this?

Full code:

    <div class="topic-content <?php if ( $thumbs_number == 2 ) { echo "high-rated"; } ?>">
        <span class="topic-author-link"><?php bbp_reply_author_link( array( 'type' => 'name' ) ); ?></span>
        <span class="topic-post-date"><?php printf( __( '<span>%1$s</span> <span>at %2$s</span>', 'bbpress' ), get_the_date(), esc_attr( get_the_time() ) ); ?></span>

<?php echo time_ago(); ?>
<br />
<?php echo "$post->post_modified 
"; ?>

        <?php bbp_reply_admin_links(); ?>

        <?php bbp_reply_content(); ?>

        <div class="topic-like-count">
            <h4><?php wp_gdsr_render_article_thumbs(); ?></h4>

            <?php preg_match( '!<div class="thumblock ">(.*)</div>!si' , wp_gdsr_render_article_thumbs(0, false, "", 0, "", false) , $n );
            $thumbs_number = strip_tags( $n[1] ); ?>

            <?php echo $thumbs_number; ?>

        </div>

Answer 1

The output is "nothing" because you have it in your HTML syntax. You should view the source to see what is has outputted.