通过传递特定模式替换中间字符串

Question

I want to replace a middle string by passing the pattern. I have tried it by using pre_replace function. But it is not working for me.

   $str = "Lead for Nebhub - Admark
          Name: Punam Kalbande
          Email: [e-mail]
          Phone Number: 800-703-3209
          Nebhub Partner : Nebhub - Admark
          Address: PO Box 830395 Miami, FL 33173
          Hub : Automotive
          Products: ERP, CRM, HCM, Help Desk, Marketing";
  $pattern = '/^Hub :(.+)Products:$/i';
  $replacement = "Logistics";
  $result = preg_replace($pattern, $replacement, $str);

but the above code is only returning original string. It is not replacing with the new one.

Answer 1

The s-Modifier is missing in your Pattern. Further you want to match the Pattern somewhere in the middle of the Text. You used ^, which indicates the Start of the Line and $ which indicates the End of the Line. That means, the whole String must match. Use this Regex, and it will work for you.

/(Hub :)[^
]+/is

Explanation:

(        start Subpattern
Hub      the Word Hub
         followed by a space
:        followed by a Doubledot 
)        end Subpattern -> accessible by $1 or \1
[^
]+   match one or more Characters except a Linebreak

i        Modifier for caseinsensitive Search
s        Modifier to include Linebreaks

What you have to do now is to output the Subpattern in the Replacement too:

$result = preg_replace($pattern, "$1$replacement", $str);