I have tried this piece of code which is used in a lot of examples by drupal developers, in my template.php , but when I print out the $variables array , it doesnot contain any key named 'tree'. I just need to add ul li tags to my menu block but
function atsubtheme_menu_tree(&$variables) {
return '<ul class="nav">' . $variables['tree'] . '</ul>';
}
This is how I have rendered the menu on page.tpl using the following code, which has a list of links under main menu in drupal menus
<nav id="menu">
<h2>Menu</h2>
<?php print render($page['menu_bar']); ?>
</nav>
I just need therendered menu in ul li tags.
我已经尝试过这段代码，drupal开发人员在我的template.php中使用了很多例子。 ，但是当我打印出$ variables数组时，它不包含任何名为'tree'的键。 我只需要在我的菜单块中添加ul li标签，但
function atsubtheme_menu_tree（＆amp; $ variables）{
return'＆lt; ul class =“nav”＆gt;' 。 $ variables ['tree']。 '＆lt; / ul＆gt;';
}
这是我使用以下代码在page.tpl上呈现菜单的方式，该代码包含 drupal菜单中主菜单下的链接
＆lt; nav id =“menu”＆gt;
＆lt; h2＆gt;菜单＆lt; / h2＆gt;
＆lt;？php print render （$页[ 'MENU_BAR']）; ？＆gt;
＆lt; / nav＆gt;
我只需要在ul li标签中找到收到的菜单。
Yeah, i'm also fedup with the menu drupal renderer, that's why i prefer to write my own render (in page.tpl.php) :
微信扫一扫<ul class="nav">
<?php
$mymenu = menu_tree('main-menu');
foreach($mymenu as $item){
if(!empty($item['#title'])){
$attributes = array('class'=>array('all', 'my', 'classes'), 'id'=>'an-eventual-id');
print '<li>'.l($item['#title'],$item['#href'],array('attributes'=>$attributes)).'</li>';
}
}
?>
</ul>