具有多个条件的语句[symfony2]

Question

I have an entity named verified in my table user. I would like if verified is null to show this [you can upload your application], if verified =2 to show this [your application is in process], if verified =3 your application has been verified.

but for now if verified =3 is showing the message of verified =2.

This is what i have done:

 {% if entity.verified is empty %}

<p>
you can upload your application
</p>

{% elseif entity.verified|length !=2 %}

<p>
your application is in process
</p>

{% elseif entity.verified|length !=3 %}

<p>
your application has been verified
</p>
 {% endif %}

User.php

/**
 *
 * @ORM\Column(name="verified", type="decimal", options={"default" : 0}, nullable=true)
 */
protected $verified;

/**
 * Set verified
 *
 * @param string $verified
 * @return User
 */
public function setVerified($verified)
{
    $this->verified = $verified;

    return $this;
}

/**
 * Get verified
 *
 * @return string 
 */
public function getVerified()
{
    return $this->verified;
}

Answer 1

You don't need to use the length filter (the scope of that filter is for count the element of an array, collection etc), so try simple:

{% if entity.verified is empty %}    
    <p>you can upload your application</p>
{% elseif entity.verified == 2 %}
    <p>your application is in process</p>
{% elseif entity.verified == 3 %}
    <p>your application has been verified</p>
{% endif %}

And invert the condition.

Hope this help