2016-08-11 09:29 阅读 116


I wrote a PHP script that processes some task for me (specifically, encoding videos on a media server). I tested calling this script via python like so:

proc = subprocess.Popen("php vodworkflow_drm_playready_widevine.php videos " +str(video), shell=True, stdout=subprocess.PIPE)

This worked correctly (i.e. the video name passed to the script got correctly encoded and such). However, when I call Popen from inside my Django project, I instead get the output: Could not open input file: my_script.php.

I'm stumped! Can anyone help with what could be going on, and what I can do to rectify this? Thanks, I've been stuck since a while now. Do let me know if you need to see the PHP script and more detailed code.

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