dswqz24846 2016-03-07 06:22
浏览 58

Php - 使用路径(PDO)从数据库显示图像

I tried to display image from database,

  • image in directory
  • path in database

    require_once "Connection.php";
    class DisplayDataImageProfile {
    function showImageProfile(){
        $connection = new Connection();
        $conn = $connection->getConnection();
    
        $id = $_GET['id'];
    
        try{
            $sqlDisplay = "SELECT photo FROM frofile WHERE id =$id";
            $getImage = $conn->prepare($sqlDisplay);
            $getImage->execute();
            $getImage->fetchAll(PDO::FETCH_ASSOC);
    
            foreach($getImage as $data){
                header('Content-type: image/jpg');
                // echo "<img src='$data'>";
                echo $data;
            }
    
        }catch (PDOException $e){
            echo "Error : " + $e->getMessage();
        }
    }}
    

after that i call in html page like this :

<img src="DisplayDataImageProfile .php?id=3" align="center" />

i got problem that image cannot retrieve from database using path. other case on webpage the image something like broken image displayed.

for currently i just display one image.

  • 写回答

2条回答 默认 最新

  • douluo6626 2016-03-07 06:25
    关注

    You need to use $data as:

    $data['photo']
    

    instead of just

    $data
    

    Because $getImage consist on associative array, so you can not use like your example, you need to use index for print data.

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