I am trying to get a summed field in medoo.
My sql at the moment is like:
$database->debug()->select("user_rupees_in_house", [
"[<]rupees" => ["rupee_id" => "ID"]
], [
"name",
"amount",
"amount_spend"
], [
"user_uuid" => $user,
"GROUP" => "rupee_id"
]);
The debug logs the following statement:
SELECT `name`,`amount`,`amount_spend`, `rupee_id`
FROM `user_rupees_in_house`
RIGHT JOIN `rupees`
ON `user_rupees_in_house`.`rupee_id` = `rupees`.`ID`
WHERE `user_uuid` = '4da9ff11-56ca3a2f-b3ab-a25b9230'
GROUP BY `rupee_id`
What I'm trying to achieve is:
SELECT `name`,SUM(`amount`),SUM(`amount_spend`), `rupee_id`
FROM `user_rupees_in_house`
RIGHT JOIN `rupees`
ON `user_rupees_in_house`.`rupee_id` = `rupees`.`ID`
WHERE `user_uuid` = '4da9ff11-56ca3a2f-b3ab-a25b9230'
GROUP BY `rupee_id`
Does anybody know how to make this statement in medoo?
[EDIT 1]
Found another way of achieving this
// Get the rupee types
$rupee_types = $database->select("rupees", "ID");
foreach ($rupee_types as $rupee_type) {
$amount = $database->sum("user_rupees_in_house", "amount", [
"AND" => [
"rupee_id" => $rupee_type,
"user_uuid" => $user
]
]);
// Build array of rupees
}
This will make a lot more calls to the database, but is working just fine as long as the SELECT
statement does not support aggregate functions.