dongyi6543 2016-02-26 18:50
浏览 282
已采纳

从json字符串中提取数据元素

I am using the following script to my php script on my server;

$.ajax({
            type: 'POST',
            url: 'http://xx.php',
            data: { anyNumber: val1 },
            success: function(data) {
                alert(data);
            }
});

the php script correct queries sqlsrv database and returns row of data that I encode with echo json_encode($rows); I then correctly receive the json string into data (as above example) When I display the data with alert(data); as above, I get the following:

"({\"id\":1,\"Username\":null,\"Category\":null,\"VIN\":null,\"Make\":null,\"Model\":null,\"Colour\":null,\"Registration\":\"12345     \",\"RegisterNumber\":null,\"EngineNo\":null,\"Branding\":null,\"Remarks\":null,\"Photo1\":null})"

I have tried various methods but cannot assign the various elements to variables. Please help

  • 写回答

1条回答 默认 最新

  • dqd54099 2016-02-26 18:55
    关注

    just set the dataType of your $.ajax call to json:

    $.ajax({
            type: 'POST',
            url: 'http://xx.php',
            dataType: 'json',
            data: { anyNumber: val1 },
            success: function(data) {
                alert(data);
            }
    });
    

    explanation: when delivering data with GET or POST a lot of characters are getting masked. I think your $.ajax call just doesn't expect JSON as an answer but text or html. that's why it's not reading the JSON string correctly and keeping the masking of the characters.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 加热反应炉PLC控制系统设计(相关搜索:梯形图)
  • ¥15 python 用Dorc包报错,我的写法和网上教的是一样的但是它显示无效参数,是什么问题
  • ¥15 经过滑动平均后的一维信号还原用什么结构好呢?
  • ¥15 指定IP电脑的访问设置
  • ¥30 matlab ode45 未发现警告,但是运行出错
  • ¥15 为什么devc++编译项目会失败啊
  • ¥15 vscode platformio
  • ¥15 代写uni代码,app唤醒
  • ¥15 全志t113i启动qt应用程序提示internal error
  • ¥15 ensp可以看看嘛.