duanlujiaji10335 2016-02-22 11:56
浏览 26
已采纳

发布人自定义PHP Json API响应

I am using postman to check my JSON API response from web applicaton to Mobile devices.

Here is my php code.

$checkout = new JsonSynchronization();
$checkout -> customer_id = isset($_POST['customer']) ? $_POST['customer'] : 0;
$checkout -> store_id = isset($_POST['store']) ? $_POST['store'] : 0;

$data ['customer_id']   = $checkout -> customer_id;
$data ['store_id']  = $checkout -> store_id;
echo json_encode($data);

enter image description here

I cant get the response as expected. What is the error?... can you please assist me ?

  • 写回答

2条回答 默认 最新

  • drno94939847 2016-02-22 12:32
    关注

    You are passing parameter in wrong place, Your parameter should go in Body tab. There your parameter will be as a post parameter, the place where you are currently sending is concatenation in URL, which is GET.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(1条)

报告相同问题?

悬赏问题

  • ¥15 #MATLAB仿真#车辆换道路径规划
  • ¥15 java 操作 elasticsearch 8.1 实现 索引的重建
  • ¥15 数据可视化Python
  • ¥15 要给毕业设计添加扫码登录的功能!!有偿
  • ¥15 kafka 分区副本增加会导致消息丢失或者不可用吗?
  • ¥15 微信公众号自制会员卡没有收款渠道啊
  • ¥100 Jenkins自动化部署—悬赏100元
  • ¥15 关于#python#的问题:求帮写python代码
  • ¥20 MATLAB画图图形出现上下震荡的线条
  • ¥15 关于#windows#的问题:怎么用WIN 11系统的电脑 克隆WIN NT3.51-4.0系统的硬盘