douchui1657
2015-12-25 19:16
浏览 30
已采纳

使用FTP和php上传文件

I can't Upload the file using php because i can't send the path i got from the html file to the function FTP_PUT because it only takes string "test.txt"

How Can i send the Path to this function

PHP FILE 

$file = $_POST["file"];

// upload file
if (ftp_put($ftp_conn, $file, $file, FTP_BINARY))
  {
  echo "Successfully uploaded $file.";
  }
else
  {
  echo "Error uploading $file.";
  }

// close connection
ftp_close($ftp_conn);

HTML FILE

    

<div class="container">
 
          <div class="row">
            <div class="col-lg-12">
               <form class="well" action="Upload.php" method="post" >
                  <div class="form-group">
                    <label for="file">Select a file to upload</label>
                    <input type="file" name="file" id="file">

                   <!-- <p class="help-block">Only jpg,jpeg,png and gif file with maximum size of 1 MB is allowed.</p> -->
                  </div>
                  <input type="submit" class="btn btn-lg btn-primary" value="Upload">
                </form>
            </div>
          </div>
    </div>

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我无法使用php上传文件，因为我无法将从html文件中获取的路径发送到 函数FTP_PUT，因为它只接受字符串“test.txt”

如何将路径发送到此函数

PHP文件 

  $ file = $ _POST [“file”]; 
 
 //上传文件
if（ftp_put（$ ftp_conn，$ file，$ file，FTP_BINARY））
 {\  n echo“已成功上传$ file。”; 
} 
else 
 {
 echo“上传$ file时出错。”; 
} 
 
 //关闭连接
ftp_close（$ ftp_conn）; 
 <  / code>  
 
 
 HTML FILE  
 
 
  
 
 
 ＆lt; div class =“container”＆gt  ; 
 
＆lt; div class =“row”＆gt; 
＆lt; div class =“col-lg-12”＆gt; 
＆lt; form class =“well”action =“Upload.php”method =  “post”＆gt; 
＆lt; div class =“form-group”＆gt; 
＆lt; label for =“file”＆gt;选择要上传的文件＆lt; / label＆gt; 
  ＆lt; input type =“file”name =“file”id =“file”＆gt; 
 
＆lt;！ - ＆lt; p class =“help-block”＆gt;只有jpg，jpeg，png和gif文件 最大大小为1 MB是允许的。＆lt; / p＆gt;  - ＆gt; 
＆lt; / div＆gt; 
＆lt; input type =“submit”class =“btn btn-lg btn-primary”value =“Upload”＆gt; 
＆lt; / form＆gt; 
＆lt;  / DIV＆GT; 
＆LT; / DIV＆GT; 
＆LT; / DIV＆GT;
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3条回答 默认 最新

  • duangao7133 2015-12-25 20:05
    已采纳

    Use $_FILES["file"]["tmp_name"] instead of $_POST["file"]

    edit:

    $file = $_FILES["file"]["tmp_name"];
$file_name = $_FILES["file"]["name"];

// upload file
if (ftp_put($ftp_conn, $file_name, $file, FTP_BINARY))

    or move the uploaded file first:

    $target_path = "uploads/".basename($_FILES["file"]["name"]); 
move_uploaded_file($_FILES["file"]["tmp_name"], $target_path);
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