dtdh11647 2018-06-21 07:03
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PHP:通过引用传递数组失败

I've the following code function:

function foo(&$vett) {

    $vettore = $vett;

    $vettore[] = "ciao";

    var_dump($vettore);
}

$v = array();

foo($v);

var_dump($v);

When I dump the final array is empty. Have you any idea of what could be?

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  • douliandan7340 2018-06-21 07:08
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    Because $v never modified. Inside the function you assign the variable into another variable. So nothing ever happen to the old $vett

    try something like:

    function foo(&$vett) {
        $vett[] = "ciao";
        echo __LINE__;
        var_dump($vett);
    }
    
    $v = array();
    foo($v);
    var_dump($v);
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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