dongshan3806 2017-06-21 09:33 采纳率: 0%
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如何从codeigniter中的json数组中读取

Im trying to decode json and get value from the json code.

[{
    "restaurant_id":1,
    "menu_template_id":2,
    "add_food_item_a":1,
    "menu_category_id":1,
    "status":0
} ,
{
    "restaurant_id":1,
    "menu_template_id":2,
    "add_food_item_a":2,
    "menu_category_id":1,
    "status":0
}]

i need to read from this json and create an array with add_food_item_a and status.

currently I'm using like this

public function readJson()
    {
        $json_obj = json_decode('');
        if (isset($GLOBALS["HTTP_RAW_POST_DATA"]) && !empty($GLOBALS["HTTP_RAW_POST_DATA"])) {
            $json_text = $this->cleanMe($GLOBALS["HTTP_RAW_POST_DATA"]);
            // now insert into user table
            $json_obj = json_decode($json_text);
        }
        return $json_obj;
    }

and I call this function like

$add_food_item_a = isset($json_obj->add_food_item_a) ? $json_obj->add_food_item_a : '';

but can't read from this array of json code

  • 写回答

1条回答 默认 最新

  • dongmi0760 2017-06-21 09:47
    关注

    Are you trying to fetch the value of 'add_food_item_a' and 'status'

        <?php
    
        $json='[{
            "restaurant_id":1,
            "menu_template_id":2,
            "add_food_item_a":1,
            "menu_category_id":1,
            "status":0
        } ,
        {
            "restaurant_id":1,
            "menu_template_id":2,
            "add_food_item_a":2,
            "menu_category_id":1,
            "status":0
        }]';
    
        echo "<pre>";
        $array = json_decode($json,1);
        print_r($array);
        foreach($array as $value)
        {
            echo "
    ".$value['add_food_item_a'];
            echo "
    ".$value['status'];
        }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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