dpvhv66448 2017-04-26 18:39
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phpmailer - ajax发送参数无效的电子邮件

I'm trying to send email with Phpmailer library. It's really basic but couldn't manage to handle.

Here is my javascript code.

function sendemail() {
    var $adtext = $("#ad").val();
         var $gonderentext = $("#mail").val();
         var $mesajtext = $("#mesaj").val();
  $.ajax({

       url: '/mail.php',
      type: 'post',
       data:{action:'call_this', ad: $adtext, gonderen: $gonderentext, mesaj: $mesajtext},
       success:function(html) {
        alert("İletişim mailiniz gönderildi.");
       }


  });

}

And here is my Php file (mail.php)

<?php
 include( "class.phpmailer.php" );
 include( "class.pop3.php" );
 include( "class.smtp.php" );
if($_POST['action'] == 'call_this') {
SendMailWithGmailSMTP("deneme@senlikorg.com","İletişim Mail",$_POST['mesaj'],$_POST['mail']);


};




function SendMailWithGmailSMTP($to,$subject,$text,$maill)
{
$mail=new PHPMailer();
$mail->IsSMTP();
$mail->SMTPAuth=true;
$mail->Host="ssl://pro06.ni.net.tr:465";
$mail->Username="deneme@senlikorg.com";
$mail->Password="xxx";
$mail->From=$maill;
$mail->FromName=$text;
$mail->CharSet="iso-8859-9";
$mail->AddAddress($to);
$mail->Subject=$subject;
$mail->IsHTML(true);
$mail->Body=$text;
if($mail->Send()) return true;
else echo $mail->ErrorInfo;

}




?>

Could you please help me to figure out what's wrong? Thanks in advance. Have a wonderful night.

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2条回答 默认 最新

  • doushang1778 2017-04-26 18:48
    关注

    I believe, problem is you are using wrong param as $_POST['mail'] rather than $_POST['gonderen'] that you are sending in your ajax post data

    Try changing your php line like this:

    SendMailWithGmailSMTP("deneme@senlikorg.com","İletişim Mail",$_POST['mesaj'],$_POST['gonderen']);
    

    Also, let me know if you are getting any error on this line $mail->ErrorInfo; here !

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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