I need to do an url address that looks like website/user/username where username is coming from database. I've tried to reach it by placing a $user variable in my action function as a parameter and result looks like this website/action?user=username. But it looks kind of hinty and ugly. How can I get a desirable result?
我需要做一个看起来像 website / user / username 的网址< em> username 来自数据库。 我试图通过在我的动作函数中放置一个$ user变量作为参数来达到它，结果看起来像 website / action？user = username 。 但它看起来有点简洁和丑陋。 我怎样才能得到理想的结果？
First you need to configure url rules in config/web.php.
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'components' => [
'urlManager' => [
'enablePrettyUrl' => true,
'showScriptName' => false,
'enableStrictParsing' => false,
'rules' => [
"user/<username:\w+>"=> "controller/action"
],
],
],
]
And add url match condition in rules array like
"user/<username:\w+>"=> "controller/action"
Create. htaccess file with below url condition in web folder
RewriteEngine on
# If a directory or a file exists, use it directly
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
# Otherwise forward it to index.php
RewriteRule . index.php
And generate urls with Url helper class or Html class like below
echo Url::to(['controller/action', 'username' => 'jack']);
Or
echo Html::a('Profile', ['controller/action', 'username' => 'jack'], ['class' => 'profile-link'])
Note:- controller name, action name and username should match with Url condition. Which we define in rules array.