doulu4976 2017-02-13 23:32
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使用PHP的MySQL到JSON(我认为是口音)

I have a problem with my PHP code that will look for an entire SQL table, and then display it in JSON format.

Here, the PHP code :

<?php
*CONFIG MYSQL*
    $lat=$_GET["lat"];
    $lng=$_GET["lng"];
      $dblink = new mysqli($dbhost, $dbuser, $dbpass, $dbname);

    $command = "SELECT *, 111.045 * DEGREES(ACOS(COS(RADIANS($lat))
     * COS(RADIANS(app_lieux.lat))
     * COS(RADIANS(app_lieux.lng) - RADIANS($lng))
     + SIN(RADIANS($lat))
     * SIN(RADIANS(app_lieux.lat))))
     AS distance_in_km
    FROM app_lieux
    ORDER BY distance_in_km ASC
    LIMIT 0,5";

      $result = $dblink->query($command);
      $dbdata = array();
      while ( $row = $result->fetch_assoc())  {
        $dbdata[]=$row;
      }
    echo json_encode($dbdata);
    ?>

When i try to go to the script, i have a blank page without error. http://notaire-gilles-france.be/charleroi2/lieux.php?lat=50.44348&lng=4.43840

What's the problem? Thank you very much for your help !

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2条回答 默认 最新

  • dou91808 2017-02-15 23:53
    关注

    I just find the answer :

    $utf8 = utf8_encode($result);
    $json = json_encode($utf8);
    

    It was very simple.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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