dongxu7408 2016-12-12 09:53
浏览 25
已采纳

PHP将天数转换为渐进式dateTime

May be a simple question, but if I have a date say 3rd of December. How could I use php to get that date in a date time format with the current year?

so for 2016 it will be 2016-12-03 and 2017 2017-12-03.

I have a function that needs to calculate the next payment date, and would need to work without magic strings

  • 写回答

1条回答 默认 最新

  • duanliaoyin3171 2016-12-12 09:59
    关注

    Just use the DateTime object. You get the current year i.e. with the date-function. Or you could also use the DateTime Object again (new DateTime())->format('Y')

    $date = new DateTime();
    $date->setDate(date('Y'), 12, 3);
    echo $date->format('Y-m-d');
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 UE5 如何可以不渲染HDRIBackdrop背景
  • ¥70 2048小游戏毕设项目
  • ¥20 mysql架构,按照姓名分表
  • ¥15 MATLAB实现区间[a,b]上的Gauss-Legendre积分
  • ¥15 Macbookpro 连接热点正常上网,连接不了Wi-Fi。
  • ¥15 delphi webbrowser组件网页下拉菜单自动选择问题
  • ¥15 linux驱动,linux应用,多线程
  • ¥20 我要一个分身加定位两个功能的安卓app
  • ¥15 基于FOC驱动器,如何实现卡丁车下坡无阻力的遛坡的效果
  • ¥15 IAR程序莫名变量多重定义