PHP str_replace正在替换，但正在清除文本的其余部分

Question

I am using str_replace to replace a substring of a string however, the replacing happens but the rest of the text is disappearing.

Example of $log_text is %%clinicid=1%% clinic we have five rooms.

function strafter($string, $substring) {
  $pos = strpos($string, $substring);
  if ($pos === false)
   return $string;
  else  
   return(substr($string, $pos+strlen($substring)));
}

$log_text = '%%clinicid=1%% clinic has <b>5</b> rooms.';

if (strpos($log_text, '%%clinicid=') !== false) {
    $clinicid = strafter($log_text,'%%clinicid='); 
    $clean_clinicid = str_replace('%%','',$clinicid);
    $clinicname = $db->single("SELECT clinic_name FROM dg_clinics WHERE id = :id", array("id"=>"$clean_clinicid"));

    $clinic_id_string = '%%clinicid='.$clinicid;

    $log_text = str_replace($clinic_id_string,$clinicname,$log_text);

}

The above code gives

Aaa

only not the full text, instead of

Aaa clinic has 5 rooms.

Where am I doing wrong?

PS. if I use %%clinicid=1%% it works perfectly but with a string it doesn't work.

Answer 1

Use preg_match to get clinic id and patern for str_replace

$log_text = '%%clinicid=1%% clinic has <b>5</b> rooms.';

if (preg_match('/%%clinicid=(\d)%%/', $log_text, $m) !== false) {
   $clean_clinicid = $m[1] ."
";
   $clinicname = $db->single("SELECT clinic_name FROM dg_clinics WHERE id = :id", array("id"=>"$clean_clinicid"));
   $log_text = str_replace($m[0],$clinicname,$log_text);
}
echo $log_text;

Answer 2

You should echo out what you get for your http://php.net/manual/en/function.str-replace.php

echo "$clinic_id_string<br>";
echo "$clinicname<br>";
echo "$log_text<br>";

that should give you a hint of why it doesnt work.