donglaoe2979 2016-03-17 15:53
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PHP include()获取错误[重复]

This question already has an answer here:

I have 35.php that includes common menu for my website. 36.php page should display the menu by using include() Why doesn't this work?

My error:enter image description here

35.php is shown below;

<?php
   echo "<a href="index.htm">Home</a>
   <a href="aboutphp.html">PHP</a> 
   <a href="abouthtml.html">HTML</a>
   <a href="aboutcss.html">CSS</a> <br />";
?>

36.php is shown below;

enter code here
  <html>
  <body>
      <?php include("35.php"); ?>
      <p>About Menu is imported from 35.php file</p>
  </body>
  </html>
</div>
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1条回答 默认 最新

  • duanrang2627 2016-03-17 15:58
    关注

    You missused the ". They include the string but you also used them for the href. But that closes the string

     echo "<a href="
    

    This is where the String ends for PHP and it wants either a ; fo finish the statement or a . to connect it to another string.

    So this is what you could to to solve it:

    echo '<a href="index.htm">Home</a>
    <a href="aboutphp.html">PHP</a> 
    <a href="abouthtml.html">HTML</a>
    <a href="aboutcss.html">CSS</a> <br />';
    

    With switching the "to a ' The string symbol is now the ' and therefor the " can be used int he string normaly.

    Otherwise you could also escape the " like this \" inside the string:

        echo "<a href=\"index.htm\">Home</a> ...
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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