duanhuanzhi6431 2018-02-26 23:33
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选择php和strtotime

I have issue with strotime function in php... Here is html example of what i expect.

<select>
    <option value="2018-02-26" selected>Feb 26 - March 4</option>
    <option value="2018-02-19">Feb 19 - Feb 25</option>
    <option value="2018-02-12">Feb 12 - Feb 18</option>
    <option value="2018-02-05">Feb 05 - Feb 11</option>
</select>

And here my php code.

for ($i = 0; $i < 7; $i++) {
   $option_value = '' . date("Y-m-d", strtotime("this monday - $i week")) . '' . " / " . date("Y-m-d", strtotime("this sunday - $i week")).' / '.$i;
   $option_render = date("d/m", strtotime("this monday - $i week")) . " / " . date("d/m", strtotime("this sunday - $i week ")) . '';

}

The problem is that the php code is not rendering what i want... Here is the result of php :

<select>
            <option value="2018-03-05">05/03 / 04/03</option>
            <option value="2018-02-26">26/02 / 25/02</option>
            <option value="2018-02-19">19/02 / 18/02</option>
            <option value="2018-02-12">12/02 / 11/02</option>
            <option value="2018-02-05">05/02 / 04/02</option>
            <option value="2018-01-29">29/01 / 28/01</option>
            <option value="2018-01-22">22/01 / 21/01</option>
</select>

</div>
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1条回答 默认 最新

  • drzrdc1766788 2018-02-26 23:49
    关注
    for ($i = 0; $i < 7; $i++) {
         $option_value = date("Y-m-d", strtotime("this monday - $i week"));
         $option_render = date("M d", strtotime("this monday - ".($i+1)." week")) . " - " . date("M d", strtotime("this sunday - $i week "));
    }
    

    Check this out, testing output:

    2018-03-05 ~ Feb 26 - Mar 04
    2018-02-26 ~ Feb 19 - Feb 25
    2018-02-19 ~ Feb 12 - Feb 18
    2018-02-12 ~ Feb 05 - Feb 11
    2018-02-05 ~ Jan 29 - Feb 04
    2018-01-29 ~ Jan 22 - Jan 28
    2018-01-22 ~ Jan 15 - Jan 21
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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