SQL Query将两列与另一个表中的一列进行比较（并获取两个值）

Question

Is it possible to, based on the ID value of two columns from table1, get their equivalent in table2?

My table1 looks like this:

id | origin | destiny
-- | ------ | -------
1  | 2      | 3
2  | 4      | 5

and table2, like this:

id | name
-- | ----
1  | bla
2  | asd
3  | dfg
4  | qwe
5  | tle

And I want to get something like this:

id | origin | destiny | nameOrigin | nameDestiny
-- | ------ | ------- | ---------- | -----------
1  | 2      | 3       | asd        | dfg
2  | 4      | 5       | qwe        | tle

I tried to do two queries:

SELECT
    t1.origin, 
    t1.destiny,
    t2.name
FROM 
    table1 t1 
INNER JOIN table2 t2 ON t1.origin = t2.id

and:

SELECT
    t1.origin, 
    t1.destiny,
    t2.name as destinyName
FROM 
    table1 t1 
INNER JOIN table2 t2 ON t1.destiny = t2.id

But if I delete a value from one table, the another one keeps indexing that row hence there is an undefined offset problem.

Answer 1

You can join the second table twice:

SELECT      t1.id,
            t1.origin, 
            t1.destiny,
            o.name as nameOrigin,
            d.name as nameDestiny
FROM        table1 t1 
INNER JOIN  table2 o ON t1.origin = o.id
INNER JOIN  table2 d ON t1.destiny = d.id

NB: "destiny" is not the same thing as "destination".