dtrpv60860
2017-03-10 08:27
浏览 51
已采纳

连接到xampp数据库

Am trying to connect to a xampp server but its not working this is my code: 

session_start();

define('DB_NAME', 'login');
define('DB_USER', 'root');
define('DB_PASSWORD', '');
define('DB_HOST', 'localhost');

$link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);

if ($link) {
    die('Failed to connect: ' . mysql_error());
}
$db_select = mysql_select_db(DBNAME, $link);
if (!$db_select) {
    die('Failed to connect:' . DBNAME . ':' . mysql_error());
}

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我试图连接到xampp服务器但它无法正常工作这是我的代码： < / p> 

  session_start（）; 
 
define（'DB_NAME'，'login'）; 
define（'DB_USER'，'root'）; 
define（'DB_PASSWORD'，''）;  
define（'DB_HOST'，'localhost'）; 
 
 $ link = mysql_connect（DB_HOST，DB_USER，DB_PASSWORD）; 
 
if（$ link）{
 die（'连接失败：'。mysql_error（  ）; 
} 
 $ db_select = mysql_select_db（DBNAME，$ link）; 
if（！$ db_select）{
 die（'连接失败：'。DBNAME。'：'。mysql_error（））; \  n}
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2条回答 默认 最新

  • doulan9419 2017-03-10 08:31
    已采纳

    mysql is no longer usable. use mysqli and it will work fine

    If you want to know more about it visit https://www.w3schools.com/php/func_mysqli_query.asp

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  • donglu7286 2017-03-10 08:40

    If you can solve the problem, try it with this sentence and you will see the error faster.

     <?php $servername = "localhost"; $username = "username"; $password = "password";

try {
    $conn = new PDO("mysql:host=$servername;dbname=myDB", $username, $password);
    // set the PDO error mode to exception
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    echo "Connected successfully";
    } catch(PDOException $e)
    {
    echo "Connection failed: " . $e->getMessage();
    } ?>
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