doutang1946
2016-03-08 10:35
浏览 35
已采纳

致命错误:在字符串上调用成员函数Createuser

Whenever i try to call function Createuser() it gives me this error

Fatal error: Call to a member function Createuser() on string

I really don't know why because my other functions all work.

The code where i call the function:

 $u = $_POST['username'];
  $p = $_POST['password'];
  $e = $_POST['email'];

  // attempt to create user
  $reg = $u->Createuser($u, $p, $e);

  // if an error code is sent back, it will put it in a session.
  switch ($reg) 
  {

    case 2:
      $_SESSION['err'] = 2;
      break;

    case 3:
      $_SESSION['err'] = 3;
      break;

    case 10:
      $_SESSION['err'] = 10;
      break;

And the function itself:

function Createuser($username, $password, $email)
    {
        include("connection.php");

        $info = mysqli_query($db2, "SELECT * FROM users WHERE username = '$username' AND password = '$password'");

        // If any field is not empty 
        if(($username != NULL) && ($password != NULL) && ($email != NULL))
        {
            // If the result matches break the process
            if(mysqli_num_rows($info) == 0)
            {
                // If rank is defined make it rank 0 else rank equels rank
                if($rank == NULL)
                {
                    $rank = 0;
                }
                else
                {
                    $rank = $rank;
                }

                // Insert into $table
                if(mysqli_query($db2, "INSERT INTO users VALUES(NULL, '$username', '$password', '$email', 0)"))
                {
                    return 10;
                }
            }
            else
            {
                // Return error code 3
                return 3;
            }
        }
        else
        {   
            // Return error code 2
            return 2;
        }
    }

I really hope someone could help me with this..

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3条回答 默认 最新

  • douxia2137 2016-03-08 10:49
    已采纳

    The issue you are having comes from the following section of code:

    $u = $_POST['username'];
    $p = $_POST['password'];
    $e = $_POST['email'];
    
    // attempt to create user
    $reg = $u->Createuser($u, $p, $e);
    

    You have $u being set to a string by $_POST['username'], and are then trying to call a function on that string.

    If you've previously created a variable $u which is a class User (as mentioned in a comment), then by doing $u = $_POST['username'];, you've destroyed the object and set it as a string.

    You'll need to do something like:

    $user = new User(); // or however the user object is created
    $u = $_POST['username'];
    $p = $_POST['password'];
    $e = $_POST['email'];
    
    // attempt to create user
    $reg = $user->Createuser($u, $p, $e);
    
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  • doufei4418 2016-03-08 10:41

    $reg = $u->Createuser($u, $p, $e); replace this to $reg=$user->Createuser($u, $p, $e); change the name of object.

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  • dongzhao2725 2016-03-08 11:22

    $u veriable is conflicting in this code. Please take another veriable :

    replace this :

    $u = $_POST['username'];
    

    With

    $username = $_POST['username'];
    
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