duanqinqiao4844 2015-08-11 18:14
浏览 25

按月分组并保留产品名称

I'm not sure if it's possible just with one query, but here is my problem:

SELECT 
  SUM(p.amount) AS sales,
  AVG(p.amount) AS avg,
  COUNT(p.product_id) AS total,
  pd.title 
FROM
  payments AS p 
  LEFT JOIN products AS pd 
    ON pd.id = p.product_id 
WHERE p.status = 1 
GROUP BY MONTH(p.created);

The returned result is:

Array
(
    [0] => stdClass Object
        (
            [sales] => 979.90
            [avg] => 97.990000
            [total] => 10
            [title] => Product 1
        )

    [1] => stdClass Object
        (
            [sales] => 1139.84
            [avg] => 71.240000
            [total] => 16
            [title] => Product 1
        )

    [2] => stdClass Object
        (
            [sales] => 789.89
            [avg] => 71.808182
            [total] => 11
            [title] => Product 1
        )

    [3] => stdClass Object
        (
            [sales] => 739.87
            [avg] => 56.913077
            [total] => 13
            [title] => Product 1
        )

    [4] => stdClass Object
        (
            [sales] => 569.85
            [avg] => 37.990000
            [total] => 15
            [title] => Product 1
        )

    [5] => stdClass Object
        (
            [sales] => 999.78
            [avg] => 45.444545
            [total] => 22
            [title] => Product 1
        )

    [6] => stdClass Object
        (
            [sales] => 569.91
            [avg] => 63.323333
            [total] => 9
            [title] => Product 1
        )

    [7] => stdClass Object
        (
            [sales] => 199.96
            [avg] => 49.990000
            [total] => 4
            [title] => Product 1
        )

)

Since everything is grouped by month, all the names of the products are the same.

Is there any way around this? I need this to render a jQuery Flot chart, so it needs to be grouped by month. But I want to use product titles as chart labels.

  • 写回答

1条回答 默认 最新

  • dongyishen5796 2015-08-11 19:52
    关注

    If you want to group by month but have a column that list all the products title, you could use GROUP_CONCAT like this

    SELECT 
      MONTH(p.created) AS month,
      GROUP_CONCAT(DISTINCT(pd.title) SEPARATOR ', ') AS products,
      SUM(p.amount) AS sales,
      AVG(p.amount) AS avg,
      COUNT(p.product_id) AS total
    FROM
      payments AS p 
    LEFT JOIN products AS pd 
        ON pd.id = p.product_id 
    WHERE p.status = 1 
    GROUP BY MONTH(p.created);
    

    This will give you a result like this

    | month |                        products | sales |    avg | total |
    |-------|---------------------------------|-------|--------|-------|
    |     3 | product 2, product 3, product 1 |    10 |    2.5 |     4 |
    |     4 |            product 4, product 1 |     7 | 2.3333 |     3 |
    |     5 | product 2, product 4, product 1 |    10 |    2.5 |     4 |
    |     6 |            product 2, product 3 |     6 |      2 |     3 |
    

    http://sqlfiddle.com/#!9/a52a66/5

    评论

报告相同问题?

悬赏问题

  • ¥15 求daily translation(DT)偏差订正方法的代码
  • ¥15 js调用html页面需要隐藏某个按钮
  • ¥15 ads仿真结果在圆图上是怎么读数的
  • ¥20 Cotex M3的调试和程序执行方式是什么样的?
  • ¥20 java项目连接sqlserver时报ssl相关错误
  • ¥15 一道python难题3
  • ¥15 牛顿斯科特系数表表示
  • ¥15 arduino 步进电机
  • ¥20 程序进入HardFault_Handler
  • ¥15 关于#python#的问题:自动化测试