dongxi2014 2014-10-28 10:40
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PHP正则表达式：匹配“url（）”的模式

This Regex:

$pattern = '/url\(([^)]+)\)/';

matches everything between url( ... ) in CSS files. The problem: If there are quotes, like this: url('...'), they occur in the returned phrase as well.

How to return a phrase without quotes, if there are any?

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  • dongyongan9941 2014-10-28 10:41
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    url\(['"]?([^)]+?)['"]?\)

    This should do it for you.Make ' or " optional.

    See demo.

    http://regex101.com/r/sU3fA2/27

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