如何在选择单选按钮时破坏id中的数据？

Question

How to destroy data in id when select radio button like this function ?

.....................................................................................................................................................................

First load page index.php,

1. press Check1 button, you will see text PRODUCTS DATA OK
2. checked radio button SECOND RADIO
3. checked radio button FIRST RADIO
4. you will see text PRODUCTS DATA OK

this is my question in step 2. checked radio button SECOND RADIO After checked radio button SECOND RADIO, i want to destroy text PRODUCTS DATA OK that store in <p id="myplace_data1"></p>

How can i do that ?

index.php

<script type="text/javascript" src="http://code.jquery.com/jquery.min.js"></script>

<script>
    $(document).ready(function(){
        $(".radio_id").click(function(){
            if($(this).attr("value")=="first"){
                $("#second_checkbox").hide();                
                $("#first_checkbox_display").show();
            }
            if($(this).attr("value")=="second"){
                $("#first_checkbox_display").hide();                
                $("#second_checkbox").show();    
            }
        });
    });
</script>


<form id="first_checkbox_display" name="form1" method="post" action="" ENCTYPE = "multipart/form-data" onsubmit="return checkform(this);" style=" margin: 0px; " >
<input type="text" name="products_id" value="1294759">
<input type="text" name="products_color" value="red">
<input type="text" name="products_type" value="electronic">
<input type="button" value="Check1" onclick="doajax_products_check()"/>
<p id="myplace_data1"></p>
</form>



<form id="second_checkbox" name="form2" method="post" action="" ENCTYPE = "multipart/form-data" onsubmit="return checkform(this);" style=" display: none; margin: 0px; " >
<input type="text" name="products_id" value="0000000">
<input type="text" name="products_color" value="iiiiiii">
<input type="text" name="products_type" value="aaaaaaa">
<input type="button" value="Check2" onclick="doajax_products_check2()"/>
<p id="myplace_data2"></p>
</form>
<br>
<br>
<label><input type="radio" class="radio_id" name="colorRadio" value="first" checked >FIRST RADIO</label>
<br>
<label><input type="radio" class="radio_id" name="colorRadio" value="second">SECOND RADIO</label>




<script language="javascript">
function createAjax() 
{
    var request = false;
        try {
                request = new ActiveXObject('Msxml2.XMLHTTP');
            }
        catch (err2) 
            {
                try 
                    {
                        request = new ActiveXObject('Microsoft.XMLHTTP');
                    }
                catch (err3) 
                    {
                try 
                           {
                    request = new XMLHttpRequest();
                   }
                catch (err1) 
                   {
                    request = false;
                   }
                    }
            }
    return request;
}
</script>



<script language="javascript">
function doajax_products_check(mydata){
 var ajax1=createAjax(); 
 ajax1.onreadystatechange=function(){
  if(ajax1.readyState==4 && ajax1.status==200){
   document.getElementById('myplace_data1').innerHTML=ajax1.responseText;
  }else{
   return false;
  }
 }
 ajax1.open("POST","data.php",true);
 ajax1.setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); 
 ajax1.send("products_color="+document.form1.products_color.value+"&products_type="+document.form1.products_type.value+"&products_id="+document.form1.products_id.value);
}
</script>









<script language="javascript">
function doajax_products_check2(mydata){
 var ajax1=createAjax(); 
 ajax1.onreadystatechange=function(){
  if(ajax1.readyState==4 && ajax1.status==200){
   document.getElementById('myplace_data2').innerHTML=ajax1.responseText;
  }else{
   return false;
  }
 }
 ajax1.open("POST","data.php",true);
 ajax1.setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); 
 ajax1.send("products_color="+document.form2.products_color.value+"&products_type="+document.form2.products_type.value+"&products_id="+document.form2.products_id.value);
}
</script>

data.php

<?PHP
if(isset($_POST['products_color']))
    {
        if ( $_POST['products_id'] != '' )
            { 
                if ( $_POST['products_type'] != '' )
                    {  
?>
                        <span class="taken_domain" style=" display: block; margin: 0 auto; " >PRODUCTS DATA OK</span> 
<?PHP
                    }
                 else
                    {
?>
                        <span class="taken_domain" style=" display: block; margin: 0 auto; " >NO PRODUCTS type</span> 
<?PHP
                    }
            }
        else
            { 
?>             
                <span class="taken_domain" style=" display: block; margin: 0 auto; " >NO PRODUCTS ID</span>             
<?PHP                
            }
    }
else
    {
?>
        <span class="taken_domain" style=" display: block; margin: 0 auto; " >NO PRODUCTS COLOR</span>    
<?PHP    
    }    
?>

Answer 1

Test for the checked state and the set the HTML to be blank -

if( $('input[value="second"]').is(':checked') ){
    $('#myplace_data1').html('');
    var products_id = ?; // you'll have to get the product id here
    // make AJAX call here...
    $.post( "delete_product.php", { products_id: products_id, user: user_id } );
}

All you have to do is create a PHP file that connects to the database and runs the query.

http://api.jquery.com/jquery.post/