donglin1192
2014-09-12 19:44
浏览 215
已采纳

插入数据错误代码23000 mysql pdo php

i have a table in my databse

i am trying to insert some data inside it

but i keep getting pdo error code 23000

i tried the query manually and it worked so the proplem isn't with the query

my code :

<?
include ('config.php');
$text=$_POST['text'];
if (!isset ($text)) exit();
$query=$db->prepare("INSERT INTO posts (post,userid,votes) VALUES (?,?,0)");
$query->bindValue(1,$text,PDO::PARAM_STR);
$query->bindValue(2,$id,PDO::PARAM_INT);
$re=$query->execute();
if ($re)
echo 'Added';
else die($query->errorcode()." ".$query->errorinfo());
?>

and config look like

<?
session_start();
try{
$db=new PDO ('mysql:host=localhost;dbname=test;charset=utf8','root','');
}
catch (PDOException $error) {
    echo $error->getmessage();
}
$id=$_SESSION['id'];
$username=$_SESSION['username'];
$password=$_SESSION['password'];
?>

图片转代码服务由CSDN问答提供 功能建议

我的数据库中有一个表

我想插入一些 里面的数据

但我一直得到pdo错误代码23000

我手动尝试了查询并且它有效,所以proplem没有查询

我的代码:

 &lt;?
include('config.php'); 
 $ text = $ _ POST ['  text']; 
if(!isset($ text))exit(); 
 $ query = $ db-&gt; prepare(“INSERT INTO posts(post,userid,votes)VALUES(?,?,0)”  ); 
 $的查询 - &GT; bindValue(1,$文本,PDO :: PARAM_STR); 
 $的查询 - &GT; bindValue(2,$ ID,PDO :: PARAM_INT); 
 $的重新= $查询 -  &gt; execute(); 
if($ re)
echo'已添加'; 
else die($ query-&gt; errorcode()。“”。$ query-&gt; errorinfo()); 
?&gt; \  n   
 
 

和config看起来像

 &lt;?
session_start(); 
try {
 $ db = 新的PDO('mysql:host = localhost; dbname = test; charset = utf8','root',''); 
} 
catch(PDOException $ error){
 echo $ error-&gt; getmessage();  \ N} 
 $的ID = $ _ SESSION [ 'ID']; 
 $的用户名= $ _ SESSION [ '用户名']; 
 $的密码= $ _ SESSION ['p  assword']; 
?&gt; 
   
 
  • 写回答
  • 关注问题
  • 收藏
  • 邀请回答

1条回答 默认 最新

  • dqknycyt92288 2014-09-12 19:58
    已采纳

    Did you check MySQL docs?

    http://dev.mysql.com/doc/refman/5.0/en/error-messages-server.html#error_er_dup_key

    Looks like you have a duplicate key in DB. My guess userid.

    If you have an auto-increment on userid no need to pass it on creation.

    Looking at your code it:

    1. Gets user from session
    2. Adds this user to DB

    So if you run script more than once it'll give 23000 error.

    Yes and how did userid got in to session?

    已采纳该答案
    打赏 评论

相关推荐 更多相似问题