doulian7305 2014-08-27 19:20
浏览 27
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通过ajax上传一张图片时出错[关闭]

im having trouble in uploading a single file by ajax . here is my code.

JS file

var _submit = document.getElementById('fileInputBox');
var formData = new FormData();
formData.append('upload', 'upload'); 
formData.append('SelectedFile', _submit.files[0]);

$('#fileInputBox').on('change', function (e) {
  e.preventDefault();

  $.ajax({
    url: 'upload2.php',
    type: 'POST',
    data: formData,
    dataType: 'json' ,
    async: false,
    cache: false,
    contentType: false,
    processData: false,
    success: function (data) {
       $('#sep_s').html(data.msg); 
    }

 });

  // return false;
});

HTML file

  <form action="" method="post" enctype="multipart/form-data" name="UploadForm" id="UploadForm">

     <div id="AddFileInputBox">
          <input id="fileInputBox" style="margin-bottom: 5px;" type="file"  name="file"/>
     </div>
  </form>

PHP file

  if(isset($_POST['upload']))
  {
     $ImageName         = $_FILES['file']['name'];
     $ImageSize         = $_FILES['file']['size'];
        $TempSrc        = $_FILES['file']['tmp_name'];
      $ImageType        = $_FILES['file']['type'];
    ..........

And the error im getting is

Notice: Undefined index: file in G:\installed here\upload2.php on line 16
Notice: Undefined index: file in G:\installed here\upload2.php on line 17
and so on.

whats is wrong here ?

  • 写回答

2条回答 默认 最新

  • douyue8191 2014-08-27 19:25
    关注

    You use SelectedFile as the parameter in formdata but use file in php, e.g

    $ImageName = $_FILES['SelectedFile']['name'];
    

    Also you need to get the file to upload inside the change event handler, that is when the file is actually selected.

    $('#fileInputBox').on('change', function (e) {
      var _submit = document.getElementById('fileInputBox');
      var formData = new FormData();
      formData.append('upload', 'upload'); 
      formData.append('SelectedFile', _submit.files[0]);
      ...
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
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