PHP故障保护如果无法get_contents

Question

$file = "https://www.some-api.com/?a=get_info";

$doge = (object) json_decode(file_get_contents($file));

if ($doge == false){
echo "failure";
}

else
{
[my code]
};

Every once and a while my script will fail, not all the time, simply intermittently. PHP error indicates that it's failing at the point of getting the file contents.

My attempt here with this else statement (that has not worked), was to display something different when the contents failed to be received. Is there a simple way for me to add a failsafe, so that either the script is reloaded or a different process is run if the api fails to respond properly?

Answer 1

This line will never be true...

if ($doge == false){

Given that $doge can never be false:

$doge = (object) json_decode(file_get_contents($file));

You always cast $doge to an object. You can't do that, and still check whether it's false. You need to perform the test before the cast, because...

• if file_get_contents fails, it returns false
• json_decode(false) returns NULL
• (object) NULL returns an object of type stdClass.

Therefore - it's impossible for $doge to be false, ever.

Try checking for failure before blindly json_decoding the result. Then, you don't even need the (object) cast.

$data = file_get_contents($file);

if (data) {
  $doge = json_decode($data);
  [my code]
} else {
  echo "failure";
}