修改字符串的长度，使其中的某些字符串计为1

Question

Can't seem to figure out how to do this one. Given a string I want to return the length of that string... simple enough, but I also want an array of 'search' strings within it to only count as one.

$string = 'this is [Enter]a test example of [Enter]something.';

//this can contain any number of different strings
$replace = array(
    '[Alt]',
    '[Backspace]',
    '[Ctrl]',
    '[Del]',
    '[Down]',
    '[End]',
    '[Enter]'
);

expected output for the above would be :

$string = 'this is [Enter]a test example of [Enter]something.';

// would be 50
$norm_length = strlen($string);

//where all [x]'s in above array count as 1
$length = 38;

Answer 1

Simple replace every of your keywords with a character of length one:

$string = 'this is [Enter]a test example of [Enter]something.';

//this can contain any number of different strings
$replace = array(
    '[Alt]',
    '[Backspace]',
    '[Ctrl]',
    '[Del]',
    '[Down]',
    '[End]',
    '[Enter]'
);

echo strlen(str_replace($replace, "_", $string));

(str_replace takes an array as search - no need for regex)