如果两个条件为真或另外两个为真或条件的第三部分为真，则显示HTML

Question

I have php if statement that should display certain HTML code if two conditions are true or another two are true or third part of conditions are true.

I have several arrays - $Options_arr, $MoreOptions_arr, $Special_arr .

To explain in the easiest possible way I want to do this:

if(!empty($Options_arr[0]) && $Options_arr[0]!="") or

(!empty($MoreOptions_arr[0]) && $MoreOptions_arr[0]!="") or

(!empty($Special_arr[0]) && $Special_arr[0]!="")

{?> some HTML here

All help will be appreciated thank you.

Answer 1

BragG, you can use elseif

Like:

if((!empty($Options_arr[0]) && $Options_arr[0]!="") || 
   (!empty($MoreOptions_arr[0]) &&  $MoreOptions_arr[0]!="") || 
   (!empty($Special_arr[0]) &&  $Special_arr[0]!=""))
{
 //  some html or any code
}

I hope that is what you were looking for..

Feel free to ask any question.