检查日期是周末或假日，仔细检查

Question

Ok sorry about the wording on this one but it's doing my head in, I need to find the earliest delivery date,

$useStartDate = mktime(0, 0, 0, date("m") , date("d")+1, date("Y"));

I have 2 functions

The first checks to see if a date is a weekend or a Monday and increments it accordingly

function checkWeekend ($CheckDateDate){
    if (date("w", $CheckDateDate) ==  1) { //monday
        return strtotime('+1 day', $CheckDateDate);
    }
    else if (date("w", $CheckDateDate) ==  0) { //sunday
        return strtotime('+2 day', $CheckDateDate);
    }
    else if (date("w", $CheckDateDate) ==  6) { //saturday
        return strtotime('+3 day', $CheckDateDate);
    }
    else {
        return 0;
    }
} 

The second check to see if the date is in my database of holidays

function checkHoliday ($CheckDateDate) {
    $result = mysql_query("SELECT * FROM tblNonDeliveryDates Where NonDeliveryDate = '$CheckDateDate'");
    if (mysql_num_rows($result) > 0) {
        return strtotime('+1 day', $CheckDateDate);
    }
    else {
        return 0;
    }
}

Now what I want to do is check both functions until they both return 0, Where I'm having trouble going back and checking the date is not a weekend after it's been incremented because it's a Holidays. This is what I have, but I know that it's wrong.

$CheckDate = $useStartDate;
while ($Checkdate > 0)
{
    $LastChecked = $CheckDate;
    $Checkdate = checkWeekend($CheckDate);
    $Checkdate = checkHoliday($CheckDate);
}
echo $LastChecked;

Hope that's clear.

Answer 1

You can try like this

$CheckDate = $useStartDate;
while ($Checkdate > 0)
{
    $weekend = false;
    $holiday = false;

    if( checkWeekend($Checkdate) != 0)
        $weekend = true;
    else if( checkHoliday($Checkdate) != 0)
        $holiday = true;
    else
        $Checkdate = 0;

    if( $weekend )
       $Checkdate = checkWeekend($Checkdate);
    else if( $holiday )
       $Checkdate = checkHoliday($Checkdate); 

     $LastChecked = $Checkdate;
}
echo $LastChecked;